AP Physics C: Mechanics multiple-choice practice 22 questions with answers
Free AP Physics C: Mechanics multiple-choice questions in the style of the real exam. Click an answer and it is marked straight away; then open the hint or the worked solution, one step at a time.
How the AP Physics C: Mechanics multiple-choice section works
From May 2027 the multiple-choice section has 42 questions: 42 questions in 85 minutes. It is worth 50% of your AP score, there is no penalty for a wrong answer, and each question has four options.
The questions below cover every unit. Give yourself about two minutes a question.
22 multiple-choice questions
Hint
Which component of velocity changes, and which does not?
Worked solution
- The vertical velocity is zero at the top, but the horizontal velocity is unchanged.
- So the velocity is horizontal, while the acceleration is still g downwards: C.
Hint
At rest means v = 0.
Worked solution
- v = 3t2 − 12t + 9 = 3(t − 1)(t − 3).
- v = 0 at t = 1 s and t = 3 s: B.
Hint
Third-law pairs act on two different objects and are the same type of force.
Worked solution
- The pair of “Earth pulls book (gravity)” is “book pulls Earth (gravity)”.
- The answer is B. The table's push is a different force on the same object.
Hint
Work depends on the angle between force and displacement.
Worked solution
- The normal force is perpendicular to the displacement, so cos 90° = 0.
- It does zero work: C.
Hint
F = −dU/dx. What does the force do if the particle moves slightly away?
Worked solution
- At a minimum, dU/dx = 0, so F = 0.
- Moving either way makes F point back towards the minimum, so the equilibrium is stable: B.
Hint
Momentum is conserved in every collision with no external impulse.
Worked solution
- Momentum is always conserved here; elastic means kinetic energy is conserved too.
- The answer is C.
Hint
ΣFext = Macm.
Worked solution
- With no external force, acm = 0.
- So the centre of mass moves with constant velocity (which may be zero): B.
Hint
Rotational inertia grows with mass placed far from the axis.
Worked solution
- All of the hoop's mass is at radius R; much of the disk's is closer in.
- Ihoop = MR2 > Idisk = ½MR2: A.
Hint
The one with less of its energy going into rotation moves faster.
Worked solution
- The sphere has I = (2/5)MR2, the hoop MR2.
- The sphere puts a smaller share of its energy into rotation, so it moves faster and arrives first: A.
Hint
There is no external torque about her axis.
Worked solution
- L = Iω is conserved, and I decreases, so ω increases.
- The answer is B. Her kinetic energy increases, from the work her arms do.
Hint
τ = dL/dt. Is there a torque about P?
Worked solution
- No net force acts, so there is no torque about P.
- So L = mvr⊥ is constant, with r⊥ the fixed perpendicular distance from P to the line: C.
Hint
a = −ω2x.
Worked solution
- The acceleration is proportional to the displacement.
- So it is greatest at maximum displacement: B.
Hint
Look at T = 2π√(m/k). Does A appear?
Worked solution
- The period depends only on m and k.
- So it stays the same: C. The maximum speed doubles instead.
Hint
Integrate v(t) to get x(t).
Worked solution
- x(t) = t3 − t2 + C, and x(0) = 0 gives C = 0.
- x(2) = 8 − 4.
- x = 4 m. The answer is A.
Hint
W = ∫ F dx.
Worked solution
- W = ∫02 6x dx = [3x2]02.
- = 3(4) = 12 J.
- The answer is B.
Hint
For a rod about one end, I = (1/3)ML2, which you can derive from ∫ r2 dm.
Worked solution
- I = ∫0L r2 (M/L) dr = (1/3)ML2.
- I = (1/3)(3)(22) = 4 kg·m2.
- The answer is B. (1 kg·m2 is the value about the centre.)
Hint
Energy is shared between translation and rotation. For a solid cylinder, I = (1/2)MR2.
Worked solution
- Mgh = (1/2)Mv2 + (1/2)(1/2 MR2)(v/R)2 = (3/4)Mv2.
- v = √(4gh/3) = √(4 × 9.8 × 0.9/3) = √11.76.
- v ≈ 3.43 m/s. (4.20 m/s would be sliding with no rotation.) The answer is A.
Hint
At terminal speed the net force is zero.
Worked solution
- At terminal speed, bv = mg.
- v = mg/b = (0.2)(9.8)/0.5.
- v = 3.92 m/s. The answer is A.
Hint
Impulse J = ∫ F dt.
Worked solution
- J = ∫03 4t dt = [2t2]03.
- = 2(9) = 18 N·s.
- The answer is B.
Hint
With no external torque, angular momentum is conserved.
Worked solution
- I1ω1 = I2ω2.
- (4)(3) = (2)ω2.
- ω2 = 6 rad/s. The answer is C.
Hint
A physical pendulum has T = 2π√(I/(mgd)), where d is the distance from the pivot to the centre of mass.
Worked solution
- I = (1/3)mL2 and d = L/2, so I/(mgd) = 2L/(3g).
- T = 2π√(2 × 1.5/(3 × 9.8)) = 2π√0.102.
- T ≈ 2.01 s. (2.46 s is a simple pendulum of the same length.) The answer is A.
Hint
P = Fv when the force is along the velocity.
Worked solution
- P = Fv.
- P = (50)(4) = 200 W.
- The answer is B.
Tips for the AP Physics C: Mechanics multiple-choice section
- About two minutes a question. 42 questions in 85 minutes, with calculus throughout.
- Set up before you integrate. Most errors are in the set-up: the limits, the variable, or the expression for dm or dF.
- Rotation is a big share. Know rotational inertia for rods, discs and hoops, and rolling without slipping.
- Check dimensions. An option with the wrong units can be ruled out without any calculation.
After the questions
Note every question you missed and its topic, then practise that unit: AP Physics C: Mechanics practice by unit. For a full timed test, take the practice exam, then put your score into our AP Physics C: Mechanics score calculator. For the free-response section, use the official AP Physics C: Mechanics past papers.
Frequently asked questions
Are these real AP Physics C: Mechanics exam questions?
No. They are original questions written by our tutors in the style of the exam, so each one can have a full worked solution. For real exam questions, use the official AP Physics C: Mechanics past papers.
How many multiple-choice questions are on the AP Physics C: Mechanics exam?
From May 2027, 42: 42 questions in 85 minutes. The multiple-choice section is 50% of your score.
Is there a penalty for wrong answers?
No. Only correct answers count, so answer every question, even if you have to guess.