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Geometry and measures practice problems GCSE Maths, Topic 4

Angles and polygons, area and volume, Pythagoras' theorem, right-angled trigonometry and the sine and cosine rules. Try each question before you look: use the hint if you are stuck, then reveal the worked solution one step at a time.

On this page
  1. Key equations
  2. Warm-up questions
  3. Exam-style questions
  4. Exam question practice
  5. Common mistakes
  6. Keep going

Key equations for geometry and measures

a2 + b2 = c2Pythagoras' theorem
sin θ = opp/hyp, cos θ = adj/hyp, tan θ = opp/adjtrigonometry (SOH CAH TOA)
A = ½(a + b)htrapezium
V = πr2hcylinder
a2 = b2 + c2 − 2bc cos Acosine rule (Higher)

A formulae sheet is provided in the 2025, 2026 and 2027 GCSE Maths exams. Answers within 2.5% are marked correct, and you can type fractions such as 23/20. Every topic, Foundation and Higher, is in our GCSE Maths topic list.

Warm-up questions

Quick checks on the core ideas. If these feel easy, go straight to the exam-style questions.

Q1Warm-up
Two angles in a triangle are 50° and 65°. Find the third angle.
°

Hint

Angles in a triangle add up to 180°.

Worked solution
  1. 180 − 50 − 65 = 65°.
Q2Warm-up
A trapezium has parallel sides of 6 cm and 10 cm, and a height of 4 cm. Find its area.
cm²

Hint

A = ½(a + b)h.

Worked solution
  1. ½ × (6 + 10) × 4 = 32 cm².
Q3Warm-up
Find the area of a circle with radius 5 cm, to 2 decimal places.
cm²

Hint

A = πr2.

Worked solution
  1. A = π × 52 = 25π.
  2. A = 78.54 cm².

Exam-style questions

Questions at the level of the GCSE Maths exam. The ones marked Challenge combine more than one idea.

Q4Exam-style
A right-angled triangle has shorter sides of 9 cm and 12 cm. Find the hypotenuse.
cm

Hint

Use Pythagoras' theorem.

Worked solution
  1. c2 = 92 + 122 = 225.
  2. c = 15 cm.
Q5Exam-style
In a right-angled triangle the hypotenuse is 10 cm and one angle is 35°. Find the side opposite the 35° angle, to 3 significant figures.
cm

Hint

Opposite and hypotenuse: use sine.

Worked solution
  1. sin 35° = opp/10.
  2. opp = 10 × sin 35° = 5.74 cm.
Q6Exam-style
Find the volume of a cylinder with radius 3 cm and height 10 cm, to 1 decimal place.
cm³

Hint

V = πr2h.

Worked solution
  1. V = π × 9 × 10 = 90π.
  2. V = 282.7 cm³.
Q7Exam-style
Find the size of each interior angle of a regular hexagon.
°

Hint

Each exterior angle is 360° ÷ 6.

Worked solution
  1. Exterior angle = 60°.
  2. Interior angle = 180 − 60 = 120°.
Q8ChallengeHigher
Two sides of a triangle are 7 cm and 9 cm, with an angle of 60° between them. Find the third side, to 3 significant figures.
cm

Hint

Two sides and the angle between them: use the cosine rule.

Worked solution
  1. a2 = 72 + 92 − 2 × 7 × 9 × cos 60° = 49 + 81 − 63 = 67.
  2. a = √67 = 8.19 cm.

Exam question practice

One original exam-style question in the style of a GCSE paper. Answer it in full, with working, before you open the mark scheme: most marks are for method, so show every step.

Exam-style question style · 6 points · about 6 minutes

A ladder 6.5 m long leans against a vertical wall. The top of the ladder is 6 m above the ground, which is horizontal.

  1. (a) How far is the foot of the ladder from the wall?
  2. (b) Work out the angle between the ladder and the ground, to 1 decimal place.

Write your full answer on paper first, then open the scoring guide and tick each point you earned.

Scoring guide and model answer

Part (a)

d2 = 6.52 − 62 = 42.25 − 36 = 6.25, so d = 2.5 m.

Part (b)

sin θ = 6/6.5, so θ = 67.4°.

Your mark: 0 of 6

Common mistakes in geometry and measures

Keep going

Revise the ideas behind these questions:

Then try real exam questions: GCSE Maths past papers, with official scoring guidelines. · All GCSE Maths units