Statics of a particle practice problems Edexcel IAL Mechanics 1, Chapter 4
Particles in equilibrium: resolving forces in two directions, strings at angles, limiting friction and particles held on inclined planes. Try each question before you look: use the hint if you are stuck, then reveal the worked solution one step at a time.
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Key equations for statics of a particle
| ΣFx = 0, ΣFy = 0 | equilibrium: resolve in two directions |
|---|---|
| F cos θ, F sin θ | components of a force at θ to the horizontal |
| F = μR | limiting equilibrium (on the point of moving) |
| μ = tan α | particle on the point of slipping on a plane at α, with no other forces |
Take g = 9.8 m s−2, as the WME01 paper asks, and give answers to 2 or 3 significant figures. Answers within 2.5% are marked correct, so rounding along the way is fine. Revise the methods in our A level Maths mechanics guide.
Warm-up questions
Quick checks on the core ideas. If these feel easy, go straight to the exam-style questions.
Hint
In equilibrium the forces balance.
Worked solution
- T = 2g = 2 × 9.8.
- T = 19.6 N.
Hint
This is called limiting equilibrium.
Worked solution
- When the particle is about to move, friction has reached its maximum value.
- So F = μR: C. Before that point, F < μR.
Hint
The horizontal component is next to the angle, so use cosine.
Worked solution
- 10 cos 30° = 10 × 0.866.
- = 8.66 N.
Exam-style questions
Questions at the level of the Edexcel IAL Mechanics 1 exam. The ones marked Challenge combine more than one idea.
Hint
Resolve along and perpendicular to the plane, with friction acting up the plane.
Worked solution
- Perpendicular: R = mg cos 25°. Along the plane: F = mg sin 25°.
- Limiting, so F = μR: mg sin 25° = μmg cos 25°.
- μ = tan 25° = 0.466 (3 s.f.).
Hint
Resolve along the plane so that R does not appear.
Worked solution
- Along the plane: P cos 20° = 5g sin 20°.
- P = 49 tan 20°.
- P = 17.8 N (3 s.f.).
Hint
Resolve horizontally and vertically, then solve the two equations simultaneously.
Worked solution
- Horizontally: T1 cos 30° = T2 cos 60°, so T2 = √3 T1.
- Vertically: T1 sin 30° + T2 sin 60° = 4g, so 0.5T1 + 1.5T1 = 39.2 and T1 = 19.6 N.
- T2 = 19.6√3 = 33.9 N (3 s.f.).
Hint
In equilibrium the resultant is zero, so each component adds to zero.
Worked solution
- i: 3 + a − 4 = 0, so a = 1.
- j: −2 + 5 + b = 0, so b = −3.
- The answer is A.
Hint
P reduces the normal reaction. Write R in terms of P first.
Worked solution
- Vertically: R + P sin 20° = 2g, so R = 19.6 − P sin 20°.
- Horizontally, limiting: P cos 20° = 0.5(19.6 − P sin 20°).
- P(cos 20° + 0.5 sin 20°) = 9.8, so P = 9.8/1.1107 = 8.82 N (3 s.f.).
Exam question practice
One original structured question in the style of the WME01 paper. Answer it in full, with working, before you open the mark scheme: M marks are for a correct method, A marks for accurate answers that follow from it, and B marks for a correct statement on its own.
Structured exam question style · 7 points · about 12 minutes
A particle of mass 2 kg rests on a rough plane inclined at 30° to the horizontal. The coefficient of friction between the particle and the plane is 0.25. The particle is held in equilibrium by a force of magnitude P newtons acting up the plane, along a line of greatest slope.
- (a) Find the normal reaction on the particle.
- (b) Find the least value of P for which the particle stays at rest.
- (c) Find the greatest value of P for which the particle stays at rest.
Write your full answer on paper first, then open the scoring guide and tick each point you earned.
Scoring guide and model answer
Part (a)
R = 2g cos 30° = 16.97… = 17.0 N.
Part (b)
About to slip down, so friction acts up the plane: P + 0.25R = 2g sin 30°, P = 9.8 − 4.24 = 5.56 N.
Part (c)
About to move up, so friction acts down the plane: P = 9.8 + 4.24 = 14.0 N.
Your mark: 0 of 7
Common mistakes in statics of a particle
- Using sin where cos is needed. Check: the component next to the angle uses cos.
- Putting friction in the wrong direction. Ask which way the particle is about to move, then friction opposes that.
- Taking R = mg cos α when a horizontal force also pushes into the plane.
- Writing F = μR when the question does not say the particle is on the point of moving.
Keep going
Revise the ideas behind these questions:
Then try real exam questions: Edexcel IAL Mechanics 1 past papers, with official scoring guidelines. · All Edexcel IAL Mechanics 1 units