Integration and accumulation of change practice problems AP Calculus, Unit 6
Riemann sums and the trapezoidal rule, definite integrals, the fundamental theorem of calculus, and techniques of integration. Try each question before you look: use the hint if you are stuck, then reveal the worked solution one step at a time.
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Key equations for integration and accumulation of change
| ∫ab f(x) dx = F(b) − F(a) | fundamental theorem, part 2 |
|---|---|
| d/dx ∫ax f(t) dt = f(x) | fundamental theorem, part 1 |
| ∫ xn dx = xn+1/(n + 1) + C | power rule, n ≠ −1 |
| ∫ 1/x dx = ln|x| + C | the reciprocal |
Questions marked No calculator should be done by hand, as in Part A of the multiple-choice section. You can type fractions, such as 3/4. The full sheet is in our AP Calculus formula sheet.
Warm-up questions
Quick checks on the core ideas. If these feel easy, go straight to the exam-style questions.
Hint
Antidifferentiate, then substitute the limits.
Worked solution
- An antiderivative is x3.
- 23 − 0 = 8.
Hint
Width 1, heights from the left ends: x = 0 and x = 1.
Worked solution
- Each subinterval has width 1.
- Left heights: f(0) = 0 and f(1) = 1.
- Sum = 1 × (0 + 1) = 1, an underestimate since f is increasing.
Hint
This is the fundamental theorem, part 1.
Worked solution
- The derivative of an accumulation function is the integrand at the upper limit.
- So the answer is cos(x2): B.
Exam-style questions
Questions at the level of the AP Calculus exam. The ones marked Challenge combine more than one idea.
Hint
The antiderivative of 1/x is ln x.
Worked solution
- [ln x] from 1 to e = ln e − ln 1.
- = 1 − 0 = 1.
Hint
Let u = x2 + 1. Change the limits too.
Worked solution
- u = x2 + 1, du = 2x dx; x = 0 gives u = 1, x = 1 gives u = 2.
- ∫12 u3 du = [u4/4] from 1 to 2.
- (16 − 1)/4 = 15/4 = 3.75.
Hint
Average the two ends of each strip, times its width.
Worked solution
- Strip 1: 2 × (1 + 3)/2 = 4.
- Strip 2: 2 × (3 + 7)/2 = 10.
- Total = 14.
Hint
Fundamental theorem with the chain rule: f(upper limit) × derivative of the upper limit.
Worked solution
- F'(x) = √(x2) × 2x.
- F'(2) = 2 × 4 = 8.
Hint
Average value = (1/(b − a)) ∫ab f(x) dx.
Worked solution
- ∫03 x2 dx = 9.
- Average = 9/3 = 3.
Free-response practice
One original question in the style of the exam's free-response section. Answer it in full, with working, before you open the scoring guide.
Calculator-active free-response style · 5 points · about 15 minutes
Water flows into a tank at a rate r(t) = 20 + 4t litres per minute, for 0 ≤ t ≤ 5, where t is in minutes. The tank holds 40 litres at t = 0.
- (a) How much water flows into the tank during the first 5 minutes?
- (b) Find the average rate of flow over the 5 minutes.
- (c) Water also leaks out at a constant 10 litres per minute. How much water is in the tank at t = 5?
Write your full answer on paper first, then open the scoring guide and tick each point you earned.
Scoring guide and model answer
Part (a)
∫05 (20 + 4t) dt = 100 + 50 = 150 litres.
Part (b)
150/5 = 30 litres per minute.
Part (c)
40 + 150 − 50 = 140 litres.
Your mark: 0 of 5
Common mistakes in integration and accumulation of change
- Forgetting to change the limits after a u-substitution.
- Forgetting the chain rule factor when the upper limit is a function of x.
- Mixing up left and right Riemann sums.
Keep going
Revise the ideas behind these questions:
Then try real exam questions: AP Calculus past papers, with official scoring guidelines. · All AP Calculus units