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Inequalities, explained with examples

An inequality compares two values that are not necessarily equal. Solving one is almost the same as solving an equation, with one important extra rule, and the answer is a whole range of values rather than a single number.

On this page
  1. The symbols
  2. Number lines
  3. Solving linear inequalities
  4. Worked examples
  5. Quadratic inequalities (Higher)
  6. Inequalities on graphs (Higher)
  7. Why the answer is a range
  8. Common mistakes
  9. Practice questions
  10. Frequently asked questions
  11. Key takeaways
  12. Related guides

The symbols

x > 3 means x can be any number bigger than 3, such as 3.1, 7 or 1000, but not 3 itself. x ≥ 3 includes 3. A helpful memory aid: the symbol's wide open end faces the bigger value.

Number lines

Inequalities are shown on number lines with circles and arrows. An open circle means the value is not included (< or >). A filled (solid) circle means it is included (≤ or ≥). The arrow or line shows all the values that satisfy the inequality. For −2 < x ≤ 4, draw an open circle at −2, a filled circle at 4, and a line joining them.

Solving linear inequalities

Solve an inequality like an equation: do the same to both sides. You can add or subtract any number, and multiply or divide by a positive number, without changing the sign. But there is one key rule:

When you multiply or divide both sides by a negative number, reverse the inequality sign.

Why? Start with 2 < 5, which is true. Multiply both sides by −1: −2 and −5. Now −2 is greater than −5, so the sign must flip to keep the statement true. A safe alternative is to rearrange so that the x term ends up positive, avoiding division by a negative altogether.

Worked examples

Example 1: a basic inequality

Solve 3x + 5 < 20.

Example 2: unknowns on both sides

Solve 7x − 4 ≥ 2x + 11.

Example 3: dividing by a negative

Solve 8 − 2x > 14.

Example 4: a double inequality

Solve −5 ≤ 2x + 1 < 9.

Example 5: integer solutions

List the integers n that satisfy −3 ≤ n < 4.

Example 6: a word problem

A taxi charges £3 plus £1.50 per mile. How far can you travel for at most £18?

Quadratic inequalities (Higher)

For a quadratic inequality, find the critical values by solving the quadratic equation, then decide which side of them works. A quick sketch of the parabola makes this clear.

Example 7: a quadratic inequality

Solve x² − x − 6 < 0.

Example 8: the outside region

Solve x² ≥ 16.

Inequalities on graphs (Higher)

A linear inequality in two variables, such as y < 2x + 1, describes a region of the graph. Draw the boundary line y = 2x + 1, using a dashed line for < or > (not included) and a solid line for ≤ or ≥ (included). Then test a point not on the line, such as (0, 0): 0 < 1 is true, so the region containing the origin is the one you want. Questions often ask you to shade the region satisfying several inequalities at once, then list the integer coordinates inside it.

Example 9: integer points in a region

List the integer coordinates (x, y) that satisfy y ≥ 1, x < 3 and y < x + 2.

Example 10: fractions

Solve (2x + 1)/3 > x − 2.

Why the answer is a range

An equation like 3x = 15 has one solution, but an inequality like 3x < 15 is true for infinitely many numbers. The solution x < 5 describes all of them at once. That is why exam questions ask you to show answers on number lines or list integers: they test whether you understand the whole set of solutions, not just the boundary value.

Common mistakes

Practice questions

Try each one before opening the answer.

Q1. Solve 4x − 3 ≤ 13.

Show answer
x ≤ 4.

Q2. Solve 5 − 3x < −10.

Show answer
−3x < −15, so x > 5.

Q3. List the integers satisfying 2 < 3n ≤ 12.

Show answer
2/3 < n ≤ 4: 1, 2, 3, 4.

Q4. Solve x² − 5x + 4 > 0.

Show answer
Roots 1 and 4: x < 1 or x > 4.

Frequently asked questions

Are inequalities on the Foundation paper?

Yes. Number lines, solving linear inequalities and listing integers are on both tiers. Quadratic inequalities and regions on graphs are Higher.

How do I check my answer?

Pick a value inside your solution and substitute it into the original inequality; it should be true. Then try a value just outside; it should be false.

Key takeaways