Binomial expansion, explained with examples
The binomial expansion is a quick way to expand brackets like (1 + x)<sup>8</sup> without multiplying them out by hand. It is in both years of A level Maths.
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Pascal's triangle
Expanding (a + b)n for small n shows a pattern in the coefficients:
- n = 1: 1, 1
- n = 2: 1, 2, 1
- n = 3: 1, 3, 3, 1
- n = 4: 1, 4, 6, 4, 1
- n = 5: 1, 5, 10, 10, 5, 1
Each number is the sum of the two above it. This is Pascal's triangle. It works well for small powers, but for (1 + x)12 you need a faster method.
The binomial formula for positive whole powers
(a + b)n = an + nC1an−1b + nC2an−2b² + … + nCran−rbr + … + bn
The coefficients nCr = n!/(r!(n − r)!) are the numbers in Pascal's triangle. Notice the pattern: the power of a goes down by 1 each term while the power of b goes up by 1, and the two powers always add up to n. There are n + 1 terms.
Why the coefficients are nCr
When you multiply out (a + b)n, you choose either a or b from each of the n brackets and multiply your choices together. A term containing br comes from choosing b in exactly r of the n brackets. The number of ways to choose those r brackets is nCr, which is why it appears as the coefficient. Your calculator has an nCr button: for example, 7 nCr 3 gives 35. This also explains why Pascal's triangle is symmetric: choosing r brackets for b is the same as choosing n − r brackets for a.
Worked examples
Example 1: a full expansion
Expand (1 + 2x)4.
- Coefficients from row 4: 1, 4, 6, 4, 1.
- 1 + 4(2x) + 6(2x)² + 4(2x)³ + (2x)4.
- = 1 + 8x + 24x² + 32x³ + 16x4. Put brackets around 2x so the whole term is raised to the power.
Example 2: the first few terms
Find the first three terms, in ascending powers of x, of (2 − x)6.
- 26 + 6C1(25)(−x) + 6C2(24)(−x)².
- = 64 + 6(32)(−x) + 15(16)x² = 64 − 192x + 240x².
Example 3: a specific coefficient
Find the coefficient of x³ in (3 + 2x)7.
- The x³ term has r = 3: 7C3(34)(2x)³.
- = 35 × 81 × 8x³ = 22,680x³. The coefficient is 22,680.
Example 4: finding an unknown
The coefficient of x² in (1 + kx)8 is 112. Find the possible values of k.
- The x² term is 8C2(kx)² = 28k²x².
- 28k² = 112, so k² = 4 and k = ±2.
Example 5: an approximation
Use the first three terms of (1 + x)10 to estimate 1.0110.
- (1 + x)10 ≈ 1 + 10x + 45x². Put x = 0.01.
- ≈ 1 + 0.1 + 0.0045 = 1.1045. The true value is 1.10462…, so the estimate is very close because x is small.
Negative and fractional powers (Year 2)
When n is negative or a fraction, the expansion never stops: it becomes an infinite series. Use the general form
(1 + x)n = 1 + nx + n(n − 1)x²/2! + n(n − 1)(n − 2)x³/3! + …
This series is only valid for |x| < 1. Outside that range, the terms grow instead of shrinking and the series does not converge. Exam questions almost always ask you to state the range of validity.
Example 6: a negative power
Expand (1 + x)−1 up to x³.
- n = −1: 1 + (−1)x + (−1)(−2)x²/2 + (−1)(−2)(−3)x³/6.
- = 1 − x + x² − x³, valid for |x| < 1. This matches the geometric series 1/(1 + x).
Example 7: a fractional power
Expand √(1 + 4x) up to x², and state the range of validity.
- (1 + 4x)1/2: n = 1/2 and the ‘x’ is 4x.
- 1 + (1/2)(4x) + (1/2)(−1/2)(4x)²/2 = 1 + 2x − 2x².
- Valid for |4x| < 1, so |x| < 1/4.
Example 8: when the first term is not 1
Expand (4 + x)−1/2 up to x².
- Take out the 4: 4−1/2(1 + x/4)−1/2 = ½(1 + x/4)−1/2.
- (1 + x/4)−1/2 = 1 − x/8 + (3/8)(x/4)² = 1 − x/8 + 3x²/128.
- Multiply by ½: ½ − x/16 + 3x²/256, valid for |x| < 4.
Combining with partial fractions
A common Year 2 question asks you to expand a fraction such as (5x + 3)/((1 + x)(1 + 3x)). First split it into partial fractions, then expand each part with the binomial series and add. The overall range of validity is the narrower of the two ranges.
Common mistakes
- Forgetting brackets, so 2x4 is written instead of (2x)4 = 16x4.
- Losing negative signs, especially in (a − b)n.
- Using the series for (1 + x)n without first making the first term 1.
- Forgetting to state the range of validity for negative or fractional powers.
Practice questions
Try each one before opening the answer.
Q1. Expand (1 − x)5.
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Q2. Find the coefficient of x4 in (1 + 3x)6.
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Q3. Find the term independent of x in (x + 1/x)6.
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Q4. Expand (1 + x)−2 up to x².
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Q5. Expand (1 − 2x)1/2 up to x².
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Frequently asked questions
Is the binomial expansion formula in the formula booklet?
Yes. Most boards give both the positive integer form and the general (1 + x)n series. You still need to practise using them accurately.
What is the difference between Year 1 and Year 2 binomial expansion?
Year 1 covers positive whole-number powers, which give finite expansions. Year 2 adds negative and fractional powers, which give infinite series with a range of validity.
Key takeaways
- Coefficients come from Pascal's triangle or nCr.
- Powers of a fall and powers of b rise; they add to n.
- Bracket the whole second term before raising it to a power.
- Negative and fractional powers give infinite series.
- State the range of validity: |x| < 1 for (1 + x)n.